數(shù)學分式方程兩邊同乘以(x+1)(x+10)(3x-3)5(x+10)(3x-3)-10(x+1)(3x-3)=2(x+1)(x+10)5(3x^2+27x-30)-10(3x^2-3)=2(x^2+11x+10)15x^2+135x-150-30x^2+30=2x^2+22x+2017x^2-113x+140=0解得x1=5x2=28/17經(jīng)檢驗x1x2均為原分式方程的解5/(x+1)-10/(x+10)=2/(3x-3)【5（x+10）-10（x+1）】/（x+1）（x+10）=2/（3X-3）（...