數(shù)學(xué)三角形題2，數(shù)學(xué)三角題1，數(shù)學(xué)三角形題a=2n^2+2nb=2n+1c=2n^2+2n+1a^2=4n^4+8n^3+4n^2b^2=4n^2+4n+1c^2=4n^4+4n^2+1+8n^3+4n^2+4n=a^2+b^2（勾股定理）這樣的三角形是直角三角形).2n2+2n2n+12n2+2n+1(2n2+2n+1)2-(2n2+2n)2=(2n2+2n+1-2n2-2n)(2n2+2n+1+2n2+2n)=4n2+4n+1=(2n+1)2即：(2n+1)2+(2n2+2n)2=(2n2+2n+...